The convolution square of a differentiable function need not be differentiable
Tom 160 / 2020
Colloquium Mathematicum 160 (2020), 263-267
MSC: Primary 26A16.
DOI: 10.4064/cm7894-6-2019
Opublikowany online: 7 February 2020
Streszczenie
The convolution product of a differentiable function with itself may fail to be Hölder continuous of any index on a dense set of points.
