On the diophantine equation $x^2+x+1=yz$
Volume 141 / 2015
Colloquium Mathematicum 141 (2015), 243-248
MSC: Primary 11D09.
DOI: 10.4064/cm141-2-8
Abstract
All solutions of the equation $x^2+x+1=yz$ in non-negative integers $x,y,z$ are given in terms of an arithmetic continued fraction.